37.
Through a rectangular field of length: 90m and breadth 60m, two roads are con-
structed which are parallel to the sides & cut each other at right angles through the
centre of the fields. If the width of each raod is 3m. Find :
(a)
The area covered by roads.
(b)
The cost of constructing the roads at the rate of Rs. 110 per m.
Answers
Answer:
Given length of field = 90 m
width of field = 60 m.
Area of field =90×60
Area =5400m2
length of road GEFH = 90 m.
length of road ABCD = 60 m.
width of each road = 3m [Given].
Area of roads =ar(ABCD)+ar.(GEFH)−ar(LIJK)
=90×3+60×3−3×3
=270+180−9
Area of roads =441m2.
∴ Area covered by roads =441m2.
cost of construction of roads =441×10
Total cost =4410Rs.
Given:-
Length of Rectangular field = 90m
Breadth of Rectangular field = 60m
Width of road at centre = 3m
Need To Find:-
Area of Roads
cost of constructing the roads at the rate of ₹110 per m²
Where:-
L denotes Length
B denotes Breadth
Explanation:-
[Take a look at Attachment] In this Question, We are provided with the length of Rectangular field that is 90m and Breadth that is 60m and there is small road at centre of Rectangular field of 3m that is cuts at right angles through centre of fields.
Solution:-
PQ = 3m ; QR = 60m
EF = 90m ; FG = 3m
KL = 3m
⠀⠀
Area of Rectangular Road = QR × PQ
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 60 × 3
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 180m²
Hence, Area of Rectangular road is 180m2
∴Hence,AreaofRectangularroadis180m2
⠀⠀
_____________________________________
Now, We have to find the area Rectangular road EFGH.
Area of Rectangular road EFGH = L × B
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 90 × 3
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 270m²
Hence, Area of Rectangular road is 270m^2
∴Hence,AreaofRectangularroadis270m2
