Physics, asked by infopiyush2004pbpbqm, 8 months ago

37. Two planets of same density have the ratio of their
radii as 1 : 3. The ratio of escape speed on them
will be

Answers

Answered by harshsingh803114
1

Answer:

Two planets if radii in the ratio 2 : 3 are made from the material of density in ... Then the ratio of acceleration due to gravity g1/g2 , at the surface of the ...

Explanation:

Hello,

we know that g=Gm/r²

g is acceleration due to gravity

G is gravitational constant

for 1st planet let the radius be r₁,mass be m₁,density be d₂,acceleration due to gravity be g₁

V=4/3πr³

V₁=4/3πr₁³

we know that d=m/V

m=Vd

m₁=V₁d₁

m₁=4/3πr₁³d₁

g₁=Gm₁/r₁²

g₁=G4/3πr₁³d₁/r₁²

g₁=G4/3πr₁d₁

2nd planet-let the mass be m₂,g be g₂,V be V₂,d be d₂,r be r₂

V₂=4/3πr₂³

m₂=V₂d₂

m₂=4/3πr₂³d₂

g₂=Gm₂/r₂²

g₂=G4/3πr₂³d₂/r₂²

g₂=G4/3πr₂d₂

now,g₁/g₂

(4/3πr₁d₁)/(4/3πr₂d₂)

=r₁d₁/r₂d₂

but r₁/r₂=2/3 and d₁/d₂=3/2

2×3/2×3

=1

hence g₁/g₂=1 which means

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Answered by eddie33
0

Answer:

Explanation:

Use the formula

Velocity ( escape) = √(2Gm/r)

    G is gravitational constant

     m is mass of planet

     r is radius of planet

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