Question

37. When 1.80 gm glucose dissolve in 0.99gm ofH20, the mole fraction of glucose is(1) 0.992) 0.1(3) 0.01(4) 0.90

Answer 1

2) 0.1

Explanation:

Given

mass of glucose = 1.80 g

mass of water = 0.99 g

mole fraction of glucose = ??

Solution

first find moles of water and glucose

water = 0.99/ 18

moles of water = 0.05 mol

moles of glucose n1 = 1.80 / 180

moles of glucose n2= 0.01 mol

as mole fraction of glucose X2

X2 = n2 / (n1 + n2)

X2 = 0.01 / 0.05 + 0.01

X2 = 0.16

mole fraction of glucose is 0.1