Question

372
Secondary School Mathematics for Class 10
EXERCISE 7A
1. D and E are points on the sides AB and AC respectively of a ABC
that DE || BC.
(i) If AD = 3.6 cm, AB = 10 cm and AE = 4.5 cm,
find EC and AC.​

Answer 1

Answer:

Secondary School Mathematics for Class 10

EXERCISE 7A

1. D and E are points on the sides AB and AC respectively of a ABC

that DE || BC.

(i) If AD = 3.6 cm, AB = 10 cm and AE = 4.5 cm,

find EC and AC.

Step-by-step explanation:

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Answer 2

Answer:

Answer

From given triangle, points D and E are on the sides AB and AC respectively such that DE∣∣BC.

AD=3.6 cm, AB=10 cm and AE=4.5 cm.

By Basic Proportonality Theorem:

DB

AD

=

EC

AE

Here DB=AB−AD=10−3.6=6.4 cm

⇒EC=

3.6

4.5

×6.4

or EC=8 cm

And, AC=AE+EC

AC=4.5+8=12.5 cm