Math, asked by grrygll556, 10 months ago

37x + 43y = 123
43x +37y = 117

Answers

Answered by vikastiwariniteshpan
6
  1. Step-by-step explanation:

37x+43y=123 _(1)

43x+37y=117 _(2)

eq. 1

x+y=123 - 37- 43

= 123- 80

40

eq. 2

x+y= 117- 43- 37

= 117- 80

30

x+y=40 (1)

x+y=30 (2)

Answered by MrChauhan96
357

\huge\mathfrak{Solution}

\bold{\small}\mathcal{37x+43y=123} \\ {43x+37y=117}

\bold{\small}\mathfrak{Adding\: both\:equations}

\bold{\small}\mathfrak{we\: Get,}

\bold{\small}\mathcal{80x+80y=240}

\bold{\small}\mathfrak{Taking\: 80\:common}

\bold{\small}\mathcal{80(x+y)=240}

\rule{120}2

\bold{\small}\mathcal{(x+y)=\frac{240}{80}}

\bold{\small}\mathcal{(x+y)=\cancel\frac{240}{80}}

\huge\mathcal{(x+y)= {3}}

\bold{\small}\mathfrak{Now\: subtracting\: both\:equations}

\bold{\small}\mathfrak{We\: will\:get,}

\bold{\small}\mathcal{-6x+6y=6}

\bold{\small}\mathfrak{Take\:(-6)\:common}

\small\mathfrak{Then}

\bold{\small}\mathcal{-6(x-y)=6}

\bold{\small}\mathcal{(x-y)}=\cancel\frac{6}{-6}{ -1}

\bold{\small}\mathfrak{now\: adding \: both\:new\:equations}

\bold{\small}\mathcal{x+y}={3}

\huge\mathcal{x-y}= {-1}

\rule{120}2

\bold{\huge}\mathcal{2x}=2

\huge\mathcal{x}= {1}

\bold{\small}\mathfrak{putting\: value \: of\:x}

\bold{\small}\mathfrak{we\: will\: get,}

\bold{\small}\mathcal{1+y}={3}

\bold{\small}\mathcal{y}={3-1}

\huge\mathcal{y}={2}

\bold{\huge}\mathcal{Hope\: It \: Help\:You}

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