Question

38. 0.01mole of iodoform (CHI3) reacts with excess Ag powder to produce A gas whose volume at NTP is 1. 224ml 2. 112ml 3. 336ml 4. 448ml​

Answer 1

Explanation:

2 moles of iodoform produces one mole of acetylene.

2CHI3+6Ag→C2H2+6AgI

Hence, 0.01 mol of iodoform will produce 21×0.01=0.005 mol of acetylene.

At NTP,  the volume occupied by 0.005 moles of acetylene is 0.005×22.4=0.112 L or 112 ml.