Question

_ ,38 ,_ , _ , _ , -22 solve​

Answer 1

Answer:

n=-22

a2=38

Step-by-step explanation:

a+d=38....(1)

a=a+(n-1)×d

a-23×d

a-d=23......(2)

adding 1 and 2 we get

2a=61

a=30

Answer 2

$\Large{\underline{\underline{\bf{Given:-}}}}$

$a_2 = 38 \\ \\ a_6 = - 22$

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$\Large{\underline{\underline{\bf{To\: Find:-}}}}$

$a_1 = ? \\ \\a_3 = ? \\ \\a_4 = ? \\ \\ a_5 = ?$

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$\Large{\underline{\underline{\bf{Solution:-}}}}$

${\bold{\underline{\underline{As\: we \: know \:, \: for \: an \: A.P.:-}}}}$

$⟹a_n = a + (n - 1)d \\ \\ ⟹a_2 = a + (2 - 1)d \\ \\ ⟹38 = a + d..............(i)$

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${\bold{\underline{\underline{For \: sixth \:term \: of \: A.P.:-}}}}$

$⟹a_n = a + (n - 1)d \\ \\⟹ a_6 = a + (6 - 1)d \\ \\⟹ - 22 = a + 5d...........(ii)$

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${\bold{\underline{\underline{By\: subtracting \: equation \: (I) \: from \: (ii):-}}}}$

$⟹38 - d = - 22 - 5d \\ \\⟹ 38 + 22 = - 5d + d \\ \\ ⟹60 = - 4d \\ \\ ⟹ \frac{60}{ - 4} = d \\ \\ ⟹ - 15 = d$

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${\bold{\underline{\underline{Hence,}}}}$

$༓a_1 = a_2 - d = 38 - ( - 15) = 53 \\ \\༓ a_3 = a + 2d = 53 + 2( - 15) = 23 \\ \\༓a_4 = a + 3d = 53 + 3( - 15) = 8 \\ \\༓a_5 = a + 4d = 53 + 4( - 15) = - 7$

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$\boxed{\mathfrak{\underline{Therefore, \: the \: missing \: terms \: are \: 53\: , \:23\: ,\: 8 \:, \:-7 \: respectively}}}$

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$\Large{\underline{\underline{\bf{Thanks}}}}$