Question

38) a) A machinery worth Rs 10,500 depreciated by 5%. Find its value after one year.​

Answer 1

Step-by-step explanation:

Given, principal = 10500, R = 5%, Time n = 1 year.

We know that A = P(1 + r/100)^n

⇒ 10500(1 + 5/100)^1

⇒ 10500(1 + 1/20)

⇒ 10500(21/20)

⇒ 11025.

Therefore, value after 1 year = 11025.

Hope this helps!

Answer 2

Given, principal = 10500, R = 5%, Time n = 1 year.

We know that A = P(1 + r/100)^n

⇒ 10500(1 + 5/100)^1

⇒ 10500(1 + 1/20)

⇒ 10500(21/20)

⇒ 11025.

Therefore, value after 1 year = 11025.

Hope this helps!

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