Question

38. A planet in a distant solar system is 10 times more massive than the earth and its
radius is 10 times smaller. Given that the escape velocity from the earth is 11 km/s,
the escape velocity from the surface of the planet would be
1.1.1 km/s 2. 11 km/s 34110 km/s 4. 0.11 km/s​

Answer 1

Hola here is your answer

Answer 2

The escape velocity from the surface of the planet would be 110 km/s.

Explanation:

It is given that,

A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller.

Let m is the mass of planet and r be its radius. So, ATQ :

Mass of planet, $m=10M$

Radius of planet, $r=\dfrac{R}{10}$

The escape velocity of the Earth is given by :

$v=\sqrt{\dfrac{2GM}{R}}$

The escape velocity of the planet is :

$v'=\sqrt{\dfrac{2Gm}{r}}$

$v'=\sqrt{\dfrac{2G(10M)}{(R/10)}}$

$v'=10\times \sqrt{\dfrac{2GM}{R/10}}$

$v'=10\times v$

$v'=10\times (11\ km/s)$

v' = 110 km/s

So, the escape velocity from the surface of the planet would be 110 km/s. Hence, this is the required solution.

Learn more,

Escape velocity

https://brainly.in/question/7036369