Math, asked by Khwaish1070, 3 months ago

38. A rectangular park is 82m long and 68m broad has two cross - roads 3m wide in the middle of it.
(a) Find the area of the cross - roads.
(b) Find the cost of laying tiles on the cross - roads at the rate of Rs. 50 per m2.​

Answers

Answered by saiganesh8522
0

Answer:

(a) Area of cross roads = 441 sq.m

(b) laying tiles cost is = 22,050.

Step-by-step explanation:

Area of ABCD = l×b = 5,576 sq.m

Area of EFGH = 246 sq.m

Area of IJKL = 204 sq.m

Area of MNOP = 9 sq.m

total Area of road = 246+204-9

= 441 sq.m

laying tiles = 441 × 50 = 22,050.

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