38. ABCD is a trapezium, CP and BP are bisectors of ZC and LB respectively. Find angle A
and angle D.
С
B
25°
30
P
D
A
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AP and BP are bisectors of two adjacent angles A and B of a quadrilateral ABCD.
We know that the sum of all the angles of a quadrilateral is 360°.
⇒∠A+∠B+∠C+∠D=360°, ∠A+∠B=360°−(∠D+∠C)
∴ In △PAB;
⇒∠APB+∠PAB+∠PBA=180° [ Angle sum property ]
⇒∠APB+
2
1
∠A+
2
1
∠B=180°
∴AP and BP are the bisectors of two adjacent angles A and B.
∴2∠APB+∠A+∠B=360°
⇒2∠APB=360°−(∠A+∠B)
∴2∠APB=∠C+∠D
⇒∠APB=
2
130
o
+60
o
=95°
∴x=95°.
Hence, the answer is 95°.
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