Question

38 & 39 both........

Answer 1

38>)

Q=CV

Ceff= 10×20/20+10

      =20/3μF

Since, the capacitors are connected in series, charge will be same on both C1 AND C2

Qeff= ceff×V

      =20/3× 10⁻⁶×3×10³

      =20×10⁻³

      ==> 20000μC.

39)The given circuit is in parallel connection. So, potential through all the capacitor s will be same the charge varies.

So,

Q₂=C₂ₓV

    =6ₓ10⁻⁶ₓ90

    =540μC