Question

38. An object is being thrown at a speed of 20 m
a direction 45° above the horizontal. The
taken by the object to return to the same leve
(1) 20/g
(2) 20g
(3) 20root 2/g
(4) 20/root2g
​

Answer 1

Answer:

T = 2u sin thetta/g

=

$\frac{2 \times 20}{ \sqrt{2}g }$

=

$\frac{20 \sqrt{2} }{g}$

Answer 2

Answer:

20√2/g

I hope it will help you.