38. Consider an electrical conductor connected across a potential difference V. Let delta q be a small charge moving through it in time delta t. If I is the electric current through it, (1) the kinetic energy of the charge increases by IVdelta t. (II) the electric potential energy of the charge decreases by Ivdelta t. (III) the thermal energy of the conductor increases by IV delta t. Then the correct statement/s is/ are (A) (1) (B) (1), (11) (C) (1) and (III) (D) (11), (111)
Answers
Answered by
0
Answer:
opt d will be the right one
Answered by
0
Answer: Option D is the correct answer (11) , (111) . here please look the answer.As charges move from higher to lower potential, their potential energy declines and their kinetic energy increases, which raises the thermal energy. When there is charge separation in the conductor owing to magnetic field force, an electric potential difference is created, which is given by F=q(VB).
To have F greater than zero, the conductor should travel perpendicular to the direction of B. Now, because B's path goes from L to R. So, since v should point in the direction of M, we must shift the conductor in that direction.
#SPJ3
Similar questions