Question

38. Find the zeroes of the quadratic polynomial x2 - 7x + 12 and verify the relationship
between the zeroes and the coefficients of the polynomial.​

Answer 1

Answer:

x²-7x+12=0

x²-4x-3x+12=0

x(x-4)-3(x-4)=0

(x-4)(x-3)=0

x=4 or x=3

a/q relationships

sum of zeros =4+3=7/1= -(coefficient of x) /(coefficient of x²)

product of zeros =4*3=12/1=(constant term)/(coefficient of x²)