Question

38. From the top of a cone of base radius 24 cm and height 45 cm, a cone of slant height 17cm is cut off.
What is the volume of the remaining frustum of the cone?​

Answer 1

Answer:

L2=R2+H2⇒L=242+452=2601=51cm

we know that, △OAB∼△OCD, therefore

24r=45h=5117

⇒24r=5117⇒r=324=8cm

⇒45h=5117⇒h=345=15cm

∴ Height of frustum =45−15=30cm

∴ Volume of frustum = 31π(R2+r2+Rr)h=31×

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