Question

38. Identify the product in the reaction
HC=CH
K2Cr2O7 +H2SO4
→ Product
[O]
(1) CH CHO
(3) CH,COOH
telone
Hethanal
Propene
(2) CH,CH,OH
(4) CH,OH​

Answer 1

Answer:

Explanation:

2CrO4^2- + 2H+ <=> Cr2O7^2- + H2O

…yellow ……………… orange

Once the solution is orange, no more H2SO4 will change the color. Therefore, if you start with a solution of potassium dichromate and add sulfuric acid to it it will stay orange. Therefore, this is essentially a “no reaction.”

K2Cr2O7(aq) + H2SO4(aq) → no reaction

The closest thing to a reaction is

K2Cr2O7(aq) + H2SO4(aq) <=> KHCr2O7(aq) + KHSO4(aq)

2K+ + Cr2O7^2- + H+ + HSO4^- <=> HCr2O7^ + HSO4^- + 2K+ …. ionic eqn

Cr2O7^2- + H+ <=> HCr2O7^- ………. net ionic equation