38. Sin@=1/√2 then(tan @ + cot @)=?
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sinθ=1/√2
⇒ θ = 45°
tan45° = 1
cot45° = 1
(tanθ+cotθ)= 2
⇒ θ = 45°
tan45° = 1
cot45° = 1
(tanθ+cotθ)= 2
dikshaverma4you:
Hey plzz explain it.... Didn't get it
Answered by
1
Given,
sinθ =
∴ θ = 45°
tanθ = tan45°
tanθ = 1
cotθ = cot45°
cotθ = 1
tanθ + cotθ = 1+1
tanθ + cotθ = 2
sinθ =
∴ θ = 45°
tanθ = tan45°
tanθ = 1
cotθ = cot45°
cotθ = 1
tanθ + cotθ = 1+1
tanθ + cotθ = 2
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