38. Solve the following LPP graphically. Maximize 2 = 50x + 40y Subject to constraints:
1000x + 1200y < 7600, 12x + 8y < 72, x > 0, y>0
Solve the following LPP graphically. Minimize Z = 5x + 7y Subject to constraints:
2x+y < 8, x + 2y > 10 and x,y > 0
Answers
Step-by-step explanation:
Given:
1000x+1200y < 7600
12x+8y < 72
x>0
y>0
To find:Solve the following LPP graphically. Maximize Z = 50x + 40y Subject to constraints written above.
Solution:
Tip: Convert inequations into equations and plot lines then check with inequality sign whether origin will include or not.
Step 1: Convert 1000x+1200y < 7600 into equation
1000x+1200y = 7600
Find x any y intercept by putting x=0 and y=0 and find respective y and x values.
Points are (0,6.33) and (7.6,0).
Plot these points and draw line,it is obvious that inequation contains origin because 0<7600,thus shade the portion below this line. Graph is attatched for reference.
Step 2: Convert 12x+8y < 72 into equation
12x+8y = 72
Find x any y intercept by putting x=0 and y=0 and find respective y and x values.
Points are (0,9) and (6,0).
Plot these points and draw line,it is obvious that inequation contains origin because 0<72,thus shade the portion below this line. Graph is attatched for reference.
x>0 and y> 0 indicates the first quadrant.
Step 3: Take all boundaries as well as origin (0,0)
All the boundary points are
(6,0)
(0,6.33)
(4,3)
(0,0)
Step 4:To maximize Z put these boundaries into Z and take the points of maximum value.
Z maximize at (4,3)
Z = 50x + 40y
Z=50×4+40×3
Z=200+120
Z=320
Final answer:
Graph is attatched.
Maximum value of Z is 320 at x=4 and y=3.
Hope it helps you.
Remark*: Do the second question by the same process.If find problem then ask that question alone.
To learn more:
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