38. The angle of inclination of an inclined plane is
60°. Coefficient of friction between 10kg body
on it and its surface is 0.2, g = 10 ms. The
acceleration of the body down the plane in ms2 is
1) 5.667. 2) 6.66 3) 7.66 4) Zero
Answers
Answer:
the option is 2
Explanation:
so this is the answer for this question
Therefore the acceleration of the body down the plane is 7.66 m/s². ( Option-3 )
Given:
Angle of inclination = θ = 60°
Coefficient of friction between the body and the surface = μ = 0.2
Acceleration due to gravity = g = 10 m/s²
To Find:
Acceleration of the body down the plane ( a )
Solution:
The given question can be solved as shown below.
Given that,
Angle of inclination = θ = 60°
Coefficient of friction between the body and the surface = μ = 0.2
Acceleration due to gravity = g = 10 m/s²
In the figure attached,
N = Normal Force = mg Cos θ = 10 × 10 ×Cos 60° = 50 N
f = Frictional force = μN = 0.2 × 50 = 10 N
As the body moves down,
⇒ Net Force = ma
⇒ mg Sin θ - f = ma
⇒ ( 10 × 10 × Sin 60° ) - 10 = 10a
⇒ 86.6 - 10 = 10a
⇒ 76.6 = 10a
⇒ a = 7.66
Therefore the acceleration of the body down the plane is 7.66 m/s².
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