Question

38.The following frequency distribution shows ages of employees of an office:Age (In years)Number of Employees20-25625-3016BO-351235-401040-45845-501050-5515Find the median age of the employees​

Answer 1

Answer:

Correct option is

B

42 years

Total number of elements(n) =4+16+19+28+22+8+3=100

So, median group will be group of 50

th

and 51

th

elements.

Which is 40−45 age interval.

Now, median =L+

f

m

2

n

−cf

b

×w

Where,

L= Lower class boundary of the modal group,

f

m

= Frequency of the median group

n= Total number of the median group

cf

b

= Cumulative frequency of the groups before the median class

w= Group width.

Median =40+

38

50−(4+16+19)

×5

Median =40+1.96≡42

Hence, median is 42 years.

Hence, option B.