38.The perimeter of a rectangle is 70 cm its length exceeds its breadth 5 cm. Find the area of the rectangle *
Answers
Let the breadth ,b = x cm
Therefore, the length ,l = (x+5) cm -----(i)
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀According to the Question
☯ Perimeter Rectangle = 2(l+b)
where,
- l denote length
- b denote breadth
Substitute the value we get
70 = 2(x + x+ 5)
70 = 2(2x +5)
70 = 4x + 10
70 -10 = 4x
60 = 4x
60/4 = x
x = 60/4
x = 15
- breadth = 15 cm
Putting the value of x = 15 in equation (i) we get
Length = 15 + 5
Length = 20 cm
Now, we know that
☯ Area of rectangle = l × b
substitute the value we get
Area of Rectangle = 20×15
Area of Rectangle = 300 cm²
- Hence, the area of rectangle is 300 cm².
Answer:
Given :-
- The perimeter of a rectangle is 70 cm.
- Its length exceeds its breadth is 5 cm.
To Find :-
- What is the area of the rectangle.
Formula Used :-
Perimeter of Rectangle :
Area of Rectangle :
Solution :-
Let,
Breadth of a rectangle be x cm
Length of a rectangle will be x + 5 cm
Given :
- Perimeter = 70 cm
According to the question by using the formula we get,
Hence, the required length and breadth are :
Breadth of Rectangle :
And,
Length of Rectangle :
Now, we have to find the area of the rectangle :
Given :
- Length = 20 cm
- Breadth = 15 cm
According to the question by using the formula we get,
The area of the rectangle is 300 cm².