Question

38.The perimeter of a rectangle is 70 cm its length exceeds its breadth 5 cm. Find the area of the rectangle *​

Answer 1

Step-by-step explanation:

First we need to find the length..

Perimeter if rectangle = 2(l+b)

= 2(l+5)

70 = 2l + 10

2l = 70-10

2l =60

l = 60 ÷ 2

l = 30.

Now find the area..

Area of rectangle = l × b

= 30 ×10

= 300 sq.cm.

Answer 2

Let the breadth ,b = x cm

Therefore, the length ,l = (x+5) cm -----(i)

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀According to the Question

Perimeter Rectangle = 2(l+b)

where,

l denote length

b denote breadth

Substitute the value we get

:\implies:⟹ 70 = 2(x + x+ 5)

:\implies:⟹ 70 = 2(2x +5)

:\implies:⟹ 70 = 4x + 10

:\implies:⟹ 70 -10 = 4x

:\implies:⟹ 60 = 4x

:\implies:⟹ 60/4 = x

:\implies:⟹ x = 60/4

:\implies:⟹ x = 15

breadth = 15 cm

Putting the value of x = 15 in equation (i) we get

:\implies:⟹ Length = 15 + 5

:\implies:⟹ Length = 20 cm

Now, we know that

Area of rectangle = l × b

substitute the value we get

:\implies:⟹ Area of Rectangle = 20×15

:\implies:⟹ Area of Rectangle = 300 cm²

Hence, the area of rectangle is 300 cm²

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