Question

38.
The time period of oscillations of a simple pendulum
is 1 minute. If its length is increased by 44%
then its new time period of oscillation will be
(1) 96 s
(3) 82 s
(2) 58 s
(4) 72s​

Answer 1

Answer:

may be d option 72s is the right one

Answer 2

(4) 72 s

Explanation:

Let initial length of simple pendulum,$l_1=l$

Time period, $T_1=1 minute=60 sec$

After increasing 44% in length, then

Length=$l+\frac{44}{100}l=\frac{144}{100}l$

We know that

$T=2\pi\sqrt{\frac{l}{g}}$

Where l=Length of pendulum

g=Acceleration due to gravity

Substitute the values

$T_1=2\pi\sqrt{\frac{l}{g}}$...(1)

$T_2=2\pi\sqrt{\frac{144l}{100g}}=\frac{24\pi}{10}\sqrt{\frac{l}{g}}$...(2)

Divide equation (1) by equation (2)

$\frac{T_1}{T_2}=\frac{2\pi}{\frac{24\pi}{10}}$

$\frac{60}{T_2}=\frac{10}{12}=\frac{5}{6}$

$T_2=\frac{60\times 6}{5}=72 s$

If its length is increased by 44% then its new time period of oscillation will be 72 s.

#Learn more:

https://brainly.in/question/12941632:Answered by Rockhacker