384, 432 and 1200 find out the HCF
Answers
Answered by
6
Answer:
48
Step-by-step explanation:
let a= 432
and b =384
by EDL,
432= 384×1+48
384=48×8+0
HCF(384,432)=48
now let d=1200
and c=48
by EDL,
d=cq+r
1200=48×25+0
thus,HCF(384,432,1200)=48
Answered by
0
Answer:
48
Step-by-step explanation:
Here we have to use EDL(Euclid's Division of Lemma)
so,
432 = 48 + 384 × 1 -----(i)
384 = 0 + 48 × 8 -----(ii)
1200 = 48 × 25 + 0 -----(ii)
From (i),(ii),(iii) we have 48 in common THEREFORE it is the HCF of the given numbers
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