Math, asked by adarsh8934, 7 months ago

384, 432 and 1200 find out the HCF ​

Answers

Answered by sharan0001
6

Answer:

48

Step-by-step explanation:

let a= 432

and b =384

by EDL,

432= 384×1+48

384=48×8+0

HCF(384,432)=48

now let d=1200

and c=48

by EDL,

d=cq+r

1200=48×25+0

thus,HCF(384,432,1200)=48

Answered by PrinceArunsakthi
0

Answer:

48

Step-by-step explanation:

Here we have to use EDL(Euclid's Division of Lemma)

so,

432 = 48 + 384 × 1 -----(i)

384 = 0 + 48 × 8 -----(ii)

1200 = 48 × 25 + 0 -----(ii)

From (i),(ii),(iii) we have 48 in common THEREFORE it is the HCF of the given numbers

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