Question

38a^3b^3c^3 - 19a^4b^2c ÷ 19 a^2bc​

Answer 1

Answer-

$\sf{k=2}$

Step-by-step explanation-

$\rm={\dfrac{38a^3b^3c^2-19a^4b^2c}{19a^2bc}}$

$\rm={\dfrac{38a^3b^3c^2}{19a^2bc}}-{\dfrac{19a^4b^2c}{19a^2bc}}$

$\rm=2ab^2c-a^2b=kab^2c-a^2b$

$∴\:\rm\bf{\boxed{\sf{k=2}}}$

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