Question

38percent by mass hno3 density is equal to 1.2 g/ cm3 find molarity and molality

Answer 1

Answer:

The solution have 15% (mass/volume)

let mass of solute = 15g

volume of solution = 100 ml

we have, density = 1.1g/cm

3

so, mass of solution = density∗volume=1.1×100=110g

mass of solvent(g)=110−15g

molecular mass of H

2

SO

4

=98

so, moles of H

2

SO

4

=

molecular weight

given weight

=

98

15

=0.153moles

molality =

mass of solvent(g)

moles of solute

×1000

so, molality =

95

0.153

×1000=1.6