Question

39. A body dropped from a certain height reaches the ground in 4v2s. The time taken by it to travel half of the distance after the start i​

Answer 1

Answer:

I hope you like my answer

Explanation:

Given that,

Height h=39.2 m

Initial velocity u=0

Now, from equation of motion

After crosses half distance, the acceleration due to gravity cases to act

So,

h=

2

39.2

h=19.6m

v

2

−u

2

=2gh

v

2

=2×9.8×19.6

v=19.6m/s

Hence, the velocity is 19.6 m/s