Question

39. A charge q, mass m is moving in uniform circular motion under action of a magnetic field B. Find magnetic
moment associated with the charge. Radius of circle is 'R'.
gBR
(1)
2
(2) GBR
qBR
q_BR2
(3)
(4)
2m
m​

Answer 1

Answer:

Explanation:

Let the velocity of charge q be v

the current in a circular path due to the movement of charge q is given by

i=q/T

i=q/(2π/ω) we know that v=rω ⇒  ω=v/r

i=qω/2π

i=qv/2πr

magnetic moment(μ)=iA

                               =(qv/2πr)πr²

                               =qvr/2

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