Question

39. A cricket ball is thrown into air at a speed of 16 m/s in the direction 30° above the horizontal. What is horizontal distance from the thrower to the point where it retums to same level? (take g = 10 m/s2)​

Answer 1

Answer:

22.17 m

Explanation:

horizontal distance i.e. range of projectile

R=($u^{2} *sin2$Ф )/g

u=16 m/s

Ф = 30°

g=10 m/s (acceleration due to gravity)

so,

by putting all the values into the formula

R=($16^{2} *sin2(30)$)/10

R=22.17 m

thankyou.