Question

39)
A rectangular frame of area 10m² is placed in a uniform electric field of 20Vm with normal dream on the surface
surface of the frame making 60° angle with the direction of the field. The electrie flux throw the rectangul
frame is:​

Answer 1

Explanation:

ANSWER

Given,

Electric field, E=20NC

−1

Area, A=10×10

−4

m

2

A

Electric Flux ϕ=E.Acosθ=20×10×10

−4

cos60

o

=0.01Vm