Question

39
Calculate the number of atoms present in 11:5 lit-
-res of H₂ at N.T.P2​

Answer 1

Answer:

So, 11.5 of H2 = ( 1/22.4) × 11.5 mole

= 0.51 moles of H2 gas .

Since , 1mole of H2 = 6.022 × 1023 molecules of H2 = 2× 6.022 × 1023 atoms of H2 .