Question

39. Father's age is three times the sum of his two children's age. After 5 years his age will be twice
the sum of the ages of two children. Find the age of father.​

Answer 1

Step-by-step explanation:

A father’s age is three times the age of his two sons. After 5 years, his age will be twice the sum of the ages of his sons. What is the age of the father?

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Let the age of the sons be x and y.

Given that Father’s age is three times the age of his two sons.

Therefore, present age of father is 3(x+y)

Now, it is also given, after 5 years, his age will be twice the sum of the ages of his son.

Therfore, after 5 years age of father will be 3(x+y)+5 and age of the sons will be x+5 and y+5.

3(x+y)+5 = 2(x+5+y+5)

3x+3y+5 = 2x+10+2y+10

3x+3y+5 = 2x+2y+20

3x-2x+3y-2y = 20–5

x+y = 15

Now the age of father was 3(x+y)=3(15)=45 (Putting the value of x+y)

Thus the age of the father is 45.

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