Question

39. Find the value of k, if x – 1 is a factor of
2x³ + x² – kx - 1

please give answer in long for 4 Mark's question
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Answer 1

Answer:

$\huge\star\underbrace{\mathtt\red{⫷❥ᴀ᭄} \mathtt\green{n~ }\mathtt\blue{ §} \mathtt\purple{₩}\mathtt\orange{Σ} \mathtt\pink{R⫸}}\star\:$

Step-by-step explanation:

☆Equation=>2x^3+x^2-kx-1

☆Values=>x=1(As x-1 is a factor).

=>2x^3+x^2-kx-1

=>2(1)^3+(1)^2-k-1=0 (Putting the values).

=>2+1-1-k=0

=>2-k=0

=>-k=-2

=>k=2.

☞So the value of k is 2 which is the required answer.

Mark as brainliest.

HOPE IT HELPS.

Answer 2

S O L U T I O N :

$\underline{\bf{Given\::}}$

If x-1 is a factor of p(x) = 2x³ + x² - kx - 1.

$\underline{\bf{Explanation\::}}$

As we know that factor theorem, e.g,.

(x-a) is a factor of p(x) & zero of the Polynomial p(x) = 0 So;

→ x - 1 = 0

→ x = 1

$\underline{\underline{\tt{According\:to\:the\:question\::}}}$

$\mapsto\tt{p(x) = 2x^{3} + x^{2} -kx -1=0}$

$\mapsto\tt{p(1) = 2(1)^{3} + (1)^{2} -k(1) -1=0}$

$\mapsto\tt{2 \times 1 + 1 - k - 1=0}$

$\mapsto\tt{2 \cancel{+ 1} - k \cancel{- 1}=0}$

$\mapsto\tt{2 - k=0}$

$\mapsto\tt{ \cancel{- }k=\cancel{-}2}$

$\mapsto\bf{k=2}$

Thus,

The value of k will be 2 .