Question

39.
Find the zeroes of the polynomial p(x) = x (x-2)(x+3)​

Answer 1

Answer:

hey mate

the zero of the polynomial are

(1) x-2= 0

x= 2

(2) x+3= 0

x= -3

hope it will help you

Answer 2

Answer:

The zeroes of polynomial p(x)=x(x+2)(x-3) are 0, -2 and 3

Step-by-step explanation:

Given the polynomial

p(x)=x(x+2)(x-3)p(x)=x(x+2)(x−3)

we have to find the zeroes of polynomial.

The zeroes of the polynomial are those values at which the value of polynomial is 0.

∴ To find zeroes we have to put the polynomial equals to 0

p(x)=x(x+2)(x-3)=0p(x)=x(x+2)(x−3)=0

⇒ \text{x=0, x+2=0, x-3=0}x=0, x+2=0, x-3=0

⇒ x=0, -2, 3x=0,−2,3

\text{Hence, the zeroes of polynomial p(x)=x(x+2)(x-3) are 0, -2 and 3}Hence, the zeroes of polynomial p(x)=x(x+2)(x-3) are 0, -2 and 3