Chemistry, asked by sparshhh19, 1 year ago

39 gm of an alloy of aluminium and magnesium when heated with excess of dil. HCl, forms magnesium chloride, aluminium chloride and hydrogen. The evolved hydrogen collected at 0°C has a volume of 44.8L at 1ATM pressure. Calculate composition of alloy by moles. ​

Answers

Answered by luk3004
7

applying PV=nRT for hydrogen

n=2 mole

let the mole of magnesium be x and mole of aluminium be y

Mg + 2Hcl---MgCL2 +H2

Al +3Hcl ----AlCl3 +1.5H2

NOW

24x +27y=39

x +1.5y=2

solving these two equation we get x=.5 ,y=1 percentage of magnesium=30.76% percentage of lauminium=69.24%


sparshhh19: I've seen this solution in many places but the answer is wrong. The answer should be 66.6% aluminium.
luk3004: Well this is another step but i am getting 69.24%
Answered by ben256
5

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