39) If A (-4, 8), B(-3,-4), C(0, -5) and D (5,6), are the vertices of a quadrilateral ABCD, find its area.
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Step-by-step explanation:
area[∆ABC] =
1/2 {-4(-4+5)-3(-5-8)+0(8+4)}
= 1/2{-4+39+0)
= 35/2 unit²
area [∆BCD]= 1/2{-3(-5-6)+0(6+4)+5(-4+5)
= 1/2{33+0+5}
= 19 unit ²
area of the quadrilateral= area[∆ABC]+ area [∆BCD]
= 19+17.5
= 36.5 unit²
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