Question

39. If one of the zeroes of the quadratic polynomial (k – 1)x² + kx +1 is – 3, then the value of k is
a) 4/3
b) -4/3
c) 2/3
d) -2/3​

Answer 1

Answer:

Option (a) 4/3 is the correct answer.

Step-by-step explanation:

Given, (-3) is the zeros of the polynomial

(k-1)x² + kx + 1

So, (-3) must satisfy the equation

(k-1)x² + kx + 1

(k-1) (-3)² + k(-3) +1

9(k-1) -3k + 1

9k - 9 - 3k + 1

6k = 8

k = 4/3

Hence, the value of k is 4/3.

hope it helps you.

Answer 2

Answer:

a) 4/3.

Given −3 is the zero of the polynomial (k−1)x

2 + kx+1

So −3 must satisfy the equation (k−1)x

2 + kx+1 = 0.

⟹(k−1)(−3).

2 + k(−3)+1 = 0.

⟹9(k−1)−3k+1 = 0.

⟹9k−9−3k+1 = 0.

⟹6k = 8.

⟹k = 4/3.

$thanks$