Question

39. If sin A = 1/2 and cos B = 1/2, then
(A + B) = ? *​

Answer 1

Answer:

If sin A = 1/2 and cos B = 1/2, then A + B = ? (A) 0º (B) 30º (C) 60º (D) 90º. Hence A+B = 30+60 = 90º. D is the correct answer. No answer.

Step-by-step explanation:

hope ti help to u

Answer 2

$\sf{sin\:A=\dfrac{1}{2}}\\\\\\\implies \sf{A=sin^{-1}\bigg(\dfrac{1}{2}\bigg) }\\\\\\\implies \boxed{\bf{A=30^{\circ} }}$

$\sf{cos\:B=\dfrac{1}{2}}\\\\\\\implies \sf{B=cos^{-1}\bigg(\dfrac{1}{2}\bigg) }\\\\\\\implies \boxed{\bf{B=60^{\circ} }}$

$\sf{(A+B)=30^{\circ} + 60^{\circ} }\\\\\implies \sf{(A+B)=90^{\circ} }$

(A + B) = 90°

Additional Information:

$\bullet\:\sf Trigonometric\:Values :\\\\\boxed{\begin{tabular}{c|c|c|c|c|c}Radians/Angle & 0 & 30 & 45 & 60 & 90\\\cline{1-6}Sin \theta & 0 & \dfrac{1}{2} & \dfrac{1}{\sqrt{2}} & \dfrac{\sqrt{3}}{2} & 1\\\cline{1-6}Cos \theta & 1 & \dfrac{\sqrt{3}}{2}& \dfrac{1}{\sqrt{2}}& \dfrac{1}{2}&0\\\cline{1-6}Tan \theta&0& \dfrac{1}{\sqrt{3}}&1&\sqrt{3}&Not D{e}fined\end{tabular}}$