Question

39
If x is a positive integer such that the
distance between points P(x,2) and
Q(3,-6) is 10 units then x=
o​

Answer 1

Step-by-step explanation:

Distance between two points,

PQ = 10

$\sqrt{(x - 3)^{2} + (2 - ( - 6)) ^{2} } = 10$

(x - 3)² + (2+6)² = 10²

x² -6x + 9 +8² = 100

x² - 6x + 9 +64 - 100 = 0

x² - 6x -27 = 0

x² + 3x - 9x - 27 = 0

x ( x+ 3) -9 ( x+3) = 0

(x+3)(x-9) = 0

(x+3) = 0 or (x-9) = 0

x = - 3 or x = 9

here, x is a positive integer so,

value of x = 9

I hope this will help you.

Happy to help.

Thank you.