Question

А
39. In AABC, if AD is the bisector of ZA, show
that AB > BD and AC >DC.
B
C​

Answer 1

Answer:

If AD is the bisector of ∠A of triangle ABC, show that AB>DB. 

Given AD is the bisector of ∠A of triangle ABC 

Hence ∠DAB=∠DAC 

∠BDA is the exterior angle of the ∆DAC 

Hence ∠BDA> ∠DAC 

or ∠BDA > ∠DAB Since ∠DAC=∠DAB 

→ AB > BD In a triangle sides opposite to greater angle is greater.

Step-by-step explanation:

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