Question

39. In the presence of KF, AlF3 is soluble in HF. Find the complex formed (a) K3[AlF6] (b) AlH3 (c) K[AlF3H] (d) K3[AlF3H3]

Answer 1

$AlF_3+3KF----->K_3[AlF_6]$

Hence , option (a) is correct .