Question

39.Prove that 2 (sin^6 +cos^6) -3(sin^4+cos^4)+1=0​

Answer 1

Answer:

Step-by-step explanation:

sin⁶+cos⁶= (sin²+cos²)(sin⁴+cos⁴-sin²cos²)  (By the formula of a³+b³

sin⁶+cos⁶= sin⁴+cos⁴-sin²cos²= (sin²+cos²)² -2sin²cos²-sin²cos

Hence sin⁶+cos⁶= 1-3sin²cos²

Similarly sin⁴+cos⁴= (sin²+cos²)² -2sin²cos² = 1-2sin²cos²

Now subsitute the values in your given question