Question

39
The area of square is (x2+8x+16)cm2, the
length of its side
(x-8)cm
(x-4)cm
(x+8)cm
(x+4)cm​

Answer 1

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area of square = $side{(s)}^2$

$s^2 = x^2+8x+16$

$s = \sqrt{x^2+8x+16}$

$s=\sqrt{x^2+4x+4x+16}$

$s = \sqrt{x(x+4)+4(x+4)}$

$s =\sqrt{(x+4)(x+4)}$

$s = \sqrt{(x+4)^2}$

$s = x+4$ cm

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Answer 2

Answer:

sorry I don't know about this question sorry bro or sis