39. There are two temples, one on each bank of river just opposite to each other. One temple is som
high From the top of this temple, the amples of depression of the top and foot of the other temple
are 30 and 60 respecthely Find the width of the river and the height of other temple
Answers
To find the width of the river and the height of the other temple.
Consider the 50 m high temple EC and the other temple AB on each bank of the river BC.
From the given data,
EC = 50 m


Consider the height of the other temple to be H and the width of the river be x.
Therefore, H = 50 - h.
Let DE = h.
Thus, AB = 50 - h = CD.
Using trigonometric function, tangent on angle A in, we get

Again, Using trigonometric function, tangent on angle B in , we get

Substituting the value of h, to find the value of x

Solving further, we get
x = 28.87

Therefore, the required width of the river is 28.87 m and the height of the other temple is 33.33 m.
Answer:
Height =33.33
Step-by-step explanation:
Let AB and CD be the two two temples and Bc be the width of the river.
Then ∠ ADE =30⁰ and ∠ ACB = 60⁰
Given A = 50m
∴ In Δ ABC
tan 60⁰ = AB/BC
√3 = 50/BC
BC = 50/√3
= 50√3/3
= 28.867m
and In Δ AED
tan 30⁰ = AE/ED
tan 30⁰ = AB - BE/BC
tan 30⁰ = AB - DC/BC
1/√3 = 50 - DC /50/√3
50/3 = 50 - DC
DC = 50 - 50/3
= 150/3 - 50/3
= 100/3 m
= 33.33 m
Hence the width of the river is 28.867m and height of the other temple is 33.33m.