Question

. 39. Two lines AB and CD intersect at O. (i) If ZAOC + BOD 250°, find ZAOC, ZBOD, ZAOD and ZBOC (11) If ZAOC + ZBOC + ZBOD 320°, find ZAOC, ZBOC, BOD and ZAOD (iii) If ZAOC = (2x - 3)º and ZBOC = (3x - 2), find ZAOC, ZBOC, ZBOD and ZAOD.​

Answer 1

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>>Two lines AB and CD intersect at O . If

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Two lines AB and CD intersect at O. If ∠AOC=50

o

, find ∠AOD,∠BOD and ∠BOC

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Solution

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From the figure we know that ∠AOC and∠AOD from a linear pair

It can also be written as

∠AOC+∠AOD=180

o

By substituting the values

50

o

+∠AOD=180

o

∠AOD=180

o

−50

o

∠AOD=130

o

According to the figure we know that ∠AOD and ∠BOC are vertically opposite angles

So we get

∠AOD=∠BOC=180

o

According to the figure we know that ∠AOC and ∠BOD are vertically opposite angles

So we get

∠AOC+∠BOD=50

o