39n^3(50n^2 – 98 ) ÷ 26n^2(5n – 7)
Factorise the given expression and divide that as indicated.
Answers
Answer:
39y3 (50y2 – 98) ÷ 26y2 (5y + 7) = 3y(5y - 7)Read more on Sarthaks.com -
(i) (y
2
+7y+10)÷(y+5)=
y+5
(y
2
+5y+2y+10)
=
y+5
y(y+5)+2(y+5)
=
(y+5)
(y+5)(y+2)
=y+2
(ii) (m
2
−14m−32)÷(m+2)=
m+2
(m
2
−16m+2m−32)
=
m+2
m(m−16)+2(m−16)
=
(m+2)
(m−16)(m+2)
=m−16
(iii) (5p
2
−25p+20)÷(p−1)=
p−1
(5p
2
−5p−20p+20)
=
p−1
5p(p−1)−20(p−1)
=
(p−1)
(p−1)(5p−20)
=5p−20=5(p−4)
(iv) 4yz(z
2
+6z−16)÷2y(z+8)=4yz
2y(z+8)
(z
2
+8z−2z−16)
=2z
z+8
z(z+8)−2(z+8)
=2z
(z+8)
(z−2)(z+8)
=2z(z−2)
(v) 5pq(p
2
−q
2
)÷2p(p+q)
=5pq
2p(p+q)
(p−q)(p+q)
=
2
5
q(p−q)
(vi) 12xy(9x
2
−16y
2
)÷4xy(3x+4y)=12xy
4xy(3x+4y)
[(3x)
2
−(4y)
2
]
=3
(3x+4y)
(3x+4y)(3x−4y)
=3(3x−4y)
(vii) 39y
3
(50y
2
−98)÷26y
2
(5y+7)=39y
3
×2
26y
2
(5y+7)
(25y
2
−49)
=3y
5y+7
[(5y)
2
−7
2
]
=3y
5y+7
[(5y−7)(5y+7)]
=3y(5y−7)
- 3y(5y-7) this is answer