Question

39n cube(5on square-98) %26n square (5n-7) ​

Answer 1

Answer:

Consider the prime factorization of n. n must be divisible by 2, 3 and 5. So y must be of the form

y=2a⋅3b⋅5c

and we get

y2=2a−1⋅3b⋅5c=d2

y3=2a⋅3b−1⋅5c=e3

y5=2a⋅3b⋅5c−1=f5

looking at the exponents we have

a−1≡0mod2 , b≡0mod2 , c≡0mod2 a≡0mod3 , b−1≡0mod3 , c≡0mod3 a≡0mod5 , b≡0mod5 , c−1≡0mod5

Now you have to solve those equations for the smallest possible values of a,b and c and are done.