Math, asked by swatimondal890, 10 hours ago

-39x+27x+98=-2x-28

please answer fast​

Answers

Answered by mohitkg1355
0

Answer:

3

9

+

2

7

+

9

8

=

2

2

8

{\color{#c92786}{-39x}}+{\color{#c92786}{27x}}+98=-2x-28

−39x+27x+98=−2x−28

1

2

+

9

8

=

2

2

8

{\color{#c92786}{-12x}}+98=-2x-28

−12x+98=−2x−28

2

Subtract

9

8

98

98

from both sides of the equation

1

2

+

9

8

=

2

2

8

-12x+98=-2x-28

−12x+98=−2x−28

1

2

+

9

8

9

8

=

2

2

8

9

8

-12x+98{\color{#c92786}{-98}}=-2x-28{\color{#c92786}{-98}}

−12x+98−98=−2x−28−98

3

Simplify

Subtract the numbers

Subtract the numbers

1

2

=

2

1

2

6

-12x=-2x-126

−12x=−2x−126

4

Add

2

2x

2x

to both sides of the equation

1

2

=

2

1

2

6

-12x=-2x-126

−12x=−2x−126

1

2

+

2

=

2

1

2

6

+

2

-12x+{\color{#c92786}{2x}}=-2x-126+{\color{#c92786}{2x}}

−12x+2x=−2x−126+2x

5

Simplify

Combine like terms

Combine like terms

1

0

=

1

2

6

-10x=-126

−10x=−126

6l

Divide both sides of the equation by the same term

1

0

=

1

2

6

-10x=-126

−10x=−126

1

0

1

0

=

1

2

6

1

0

\frac{-10x}{{\color{#c92786}{-10}}}=\frac{-126}{{\color{#c92786}{-10}}}

−10−10x=−10−126

7

Simplify

Cancel terms that are in both the numerator and denominator

Divide the numbers

=

6

3

5

Answered by Korino
0

Answer:

First Transpose x to one side and constants to other side

=>-39x+27x+2x = -28 - 98

Dividing by (-1)

=>39x - 27x -2x = 98+28

=>10x =126

x=126/10

x=12.6

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