Math, asked by shreya20070, 2 months ago

) 39y^3

( 50y^2

-98 ) ÷ 26y^2

(5y + 7)

Answers

Answered by gopalpvr

2

Answer:

3y (5y-7)

Step-by-step explanation:

39y^3( 50y^2-98 ) ÷ 26y^2(5y + 7)

= 39y^3( 2)( 25y^2-49 ) ÷ 26y^2(5y + 7)

= 39y^3( 2)(( 5y)^2-7^2 ) ÷ 26y^2(5y + 7)

= 39y^3( 2)( 5y-7 )(5y-7) ÷ 26y^2(5y + 7)

= 3y (5y-7)

so 39y^3( 50y^2-98 ) ÷ 26y^2(5y + 7 )= 3y (5y-7)

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