) 39y^3
( 50y^2
-98 ) ÷ 26y^2
(5y + 7)
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2
Answer:
3y (5y-7)
Step-by-step explanation:
39y^3( 50y^2-98 ) ÷ 26y^2(5y + 7)
= 39y^3( 2)( 25y^2-49 ) ÷ 26y^2(5y + 7)
= 39y^3( 2)(( 5y)^2-7^2 ) ÷ 26y^2(5y + 7)
= 39y^3( 2)( 5y-7 )(5y-7) ÷ 26y^2(5y + 7)
= 3y (5y-7)
so 39y^3( 50y^2-98 ) ÷ 26y^2(5y + 7 )= 3y (5y-7)
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